After trying this with a different box mapper program it seems we got the correct results. It would not let us enter Gyre Sage into L3 but this new program does.. weird but ohh well at least I have learned now.
I will purchase another box soon and hopefully map it fully.
I was wondering if anyone could provide me with a link to any posts regarding how they actually solve the maps? I'm very keen to find out about this and actually try some stuff myself. This stuff is very interesting.
James.
I have no idea how others do it, so this is probably baseless speculation, but I do love my baseless sepculation (as evidenced by previous posts).
This is how I believe it could be done:
First, you would somehow know tracks are 22 letters long (haven't figured this part out yet)
Then, you would look at a box, take a pack, and cards 22 packs later, in factory order, (assuming you didn't go outside of the box yet) that pack would be on the same track. So you would compile a large database with entries such as "CARD1 comes before CARD2" and then topologically sort them all (is that the right term?). Then I assume you would guess and check to fill out some blank spots. After this is complete, you would check to find the exact pattern from some boxes using your map (with arbitrary but unique labels). Of course, this is only a theory as I have never tried this before. If I'm wrong, let me know!
I am new to box mapping but after doing some research and practice runs with my friend, we decided to buy a box and give it a go. Please note when we opened the box, the boosters where in perfect piles. Everything seemed good to go! Please see see results below.
I checked for pack deletion by writing the order 5 1 2 3 4 down on a bit of paper and going through making sure this order way obeyed throughout all columns. I think that is the correct way?
1st pack: L1 - Giant Adephage - Result M1 ([ACB])
2nd pack: M1 - Boros Reckoner - Result R1 ([DB])
3rd pack: R1 - Mystic Genesis -
Result R6 (A)
(A10) Obzedat, Ghost Council
(A41) Aurelia, the Warleader
4th pack: R6 - Aurelia, the Warleader
At this stage I thought great! 4th pack and we pulled decent Mythics.
So we planned our next move.. There were no D tracks uncovered so we went for
5th pack: L3 - Gyre Sage
We entered this into the program and it did not like it so we deleted it and tried another pack. There on after it most cards pulled were not even listed on the predictions. We managed to pull a Master Biomancer at R12 later which was a correct prediction.
I was wondering if anyone could shed any light on this please as I want to buy another box but need to know if i'm doing something wrong.
Any help would be massively appreciated.
Many thanks.
You're entering after you reshuffled the packs, right? I don't think you're doing anything wrong. What packs did you pull after? What I got so far is attached. (it doesn't look wrong... yet)
Here is another idea, sorry if the wording is clunky i didn't find a better way to say it
3BB
Enchantment
You may have creature cards in your graveyard block as if they were on the battlefield. If you do treat these creatures as 2/2 black zombies.
If a creature blocking this way would be dealt lethal damage exile it.
I don't know if this effect would be too complicated but i find it an interesting take on the necromancy aspect of black.
My take on your card. See attachment.
I think it's a pretty nice card. Could be used for recurring blocker with Misthollow Griffin.
I think I'm totally ignoring the color pie, but here goes.
Flavor:
You're desperate enough to even reuse the mana from spells you cast. (need some work on this)
Card:
Residue Collector
2BB
Whenever a spell is cast, note the colored portion of that card’s mana cost.
The mana cost of spells you cast is reduced by the last noted amount and type of mana this turn. (Only the colored portion can be reduced, for example if the last noted cost was B, a spell you have with UB as its mana cost would only cost U to cast.
Usage:
Manamorphose chaining: this would reduce the hybrid cost. +1 mana for free, anyone?
Free Geralf's Messengers: That could be good.
Play an Angel of Despair for 7, following with Obzedat for 1.
One drops would be free.
Also, the turn you play this, you also get a 2 black mana reduction for your next spell (therefore not necessarily replacing a 4 drop in your deck)
This card could also encourage monoblack in a format filled with guilds.
Switching rows 5<->3 fixes some things, but row 6 is still out of order. Maybe row 8 should be between rows 5 and 6? I can't find good rows switches thanks to the 545 on row 9, where the right-column 5-pack was probably inserted. The bottom 4 rows seem to be even harder to solve.
Seeing as you have seven 1's, six 2's, seven 3's, eight 4's, and eight 5's, you probably got a removed 2. And since you have one more 4 and one more 5 than usual (7) your pattern would either be:
5 4 x x x
4 5 x x x
because the pattern must start with a number and end with the same number in a normal box. However, since you have a removed 2, everything shifts back by 1, making the second term of the pattern the top right pack.
Now, because every single 5 is usually followed by a 4, I think it's safe to conclude that your pattern is
5 4 x x x
Using the same logic, 2 shows up after 3 many times, so your pattern should be
5 4 3 2 1
Now we have that out of the way, we'll try to start from the top down, see how that turns out.
Since we determined the top middle and top right packs should be 5 and 4, respectively, your first row should be shifted.
However, here's where my reasoning gets sketchy (it's probably inaccurate)
First, we look at the second and third rows. To fit together, they're missing a 2. Maybe that's where our removed pack is (so we keep that in mind). Now we can move the first row- it is now the third row.
Is there any data at all on Belgium boxes for GTC? I've look through the thread, but I couldn't find one box of Belgium (although I may have missed a post or two). I'm pretty sure they still print some boxes in Belgium, just not English.
When the 2 is removed, does the card that's supposed to be in that position stay the same? Or does the card become "missing" and the rest of the cards continue on? (latter case is much harder to program, I think)
EDIT: Example,
Your card list was originally
Card 1 Card 2 Card 3
Card 4 Card 5 Card 6
Card 7 Card 8 Card 9 ...
And the sleeve order is
524 413 <- the 2 was missing
135
There are 3 types i've seen.
1. removing from stack,
2. replacing the pack with another (position is the same)
3. insertion
This is done to make sure boxes are evenly distributed. Thus, the removed / replaced / inserted booster either makes the box distinctly better than others, or the opposite, it makes the box distinctly worse than others.
Comments would be nice on the code (esp. since I don't program in Java)
BTW, does anyone have any information on pack removals? I still don't understand 100%.
I have no idea how others do it, so this is probably baseless speculation, but I do love my baseless sepculation (as evidenced by previous posts).
This is how I believe it could be done:
First, you would somehow know tracks are 22 letters long (haven't figured this part out yet)
Then, you would look at a box, take a pack, and cards 22 packs later, in factory order, (assuming you didn't go outside of the box yet) that pack would be on the same track. So you would compile a large database with entries such as "CARD1 comes before CARD2" and then topologically sort them all (is that the right term?). Then I assume you would guess and check to fill out some blank spots. After this is complete, you would check to find the exact pattern from some boxes using your map (with arbitrary but unique labels). Of course, this is only a theory as I have never tried this before. If I'm wrong, let me know!
You're entering after you reshuffled the packs, right? I don't think you're doing anything wrong. What packs did you pull after? What I got so far is attached. (it doesn't look wrong... yet)
My take on your card. See attachment.
I think it's a pretty nice card. Could be used for recurring blocker with Misthollow Griffin.
Hello.
Typically, we arrange the box in this order:
So your box:
And your pattern is 1 5 4 3 2.
Flavor:
You're desperate enough to even reuse the mana from spells you cast. (need some work on this)
Card:
Residue Collector
2BB
Whenever a spell is cast, note the colored portion of that card’s mana cost.
The mana cost of spells you cast is reduced by the last noted amount and type of mana this turn. (Only the colored portion can be reduced, for example if the last noted cost was B, a spell you have with UB as its mana cost would only cost U to cast.
Usage:
Manamorphose chaining: this would reduce the hybrid cost. +1 mana for free, anyone?
Free Geralf's Messengers: That could be good.
Play an Angel of Despair for 7, following with Obzedat for 1.
One drops would be free.
Also, the turn you play this, you also get a 2 black mana reduction for your next spell (therefore not necessarily replacing a 4 drop in your deck)
This card could also encourage monoblack in a format filled with guilds.
Thoughts (other than the color being wrong)?
Here's my guess:
Start of your box:
Pattern is B D G S O
Now move 7 to 8 as you say
Move the first row to the fourth
Not sure about this part but you wanted a fast answer so...
The second and third row's packs have shifted
Red goes left and under, blue goes right and above (relative to that ^^^)
Then the first row shifts down one row
And you have one pack removal left column, third row.
Just my two cents.
Which row is the left side of the box? If the top row is the left, it would work.
Edit: Here's my line of thought. It isn't complete though.
Start:
Seeing as you have seven 1's, six 2's, seven 3's, eight 4's, and eight 5's, you probably got a removed 2. And since you have one more 4 and one more 5 than usual (7) your pattern would either be:
because the pattern must start with a number and end with the same number in a normal box. However, since you have a removed 2, everything shifts back by 1, making the second term of the pattern the top right pack.
Now, because every single 5 is usually followed by a 4, I think it's safe to conclude that your pattern is
Using the same logic, 2 shows up after 3 many times, so your pattern should be
Now we have that out of the way, we'll try to start from the top down, see how that turns out.
Since we determined the top middle and top right packs should be 5 and 4, respectively, your first row should be shifted.
However, here's where my reasoning gets sketchy (it's probably inaccurate)
First, we look at the second and third rows. To fit together, they're missing a 2. Maybe that's where our removed pack is (so we keep that in mind). Now we can move the first row- it is now the third row.
And now the logical part is over. If you want to know what I've been thinking after this (just for fun), I'll post it here.
The only way for this to work is if the fourth and sixth rows are swap (can that even happen?)
Move the seventh row so that it's the ninth (that definitely shouldn't happen!)
The I suppose the whole bottom half gets flipped, with each row (totally speculation now)
The the bottom two rows do some kind of wacky change
And voila.
Now that I read it over, that seems extremely dumb. Oh well, it was for fun after all...
http://www.wizards.com/magic/magazine/Article.aspx?x=mtg/daily/arcana/1207
This is what I have so far (could be wrong):
Original
Then it may have shifted like this:
And then a swap (X's moved)
Then the red one moved back:
But that top half, I don't know. (everything after the red line matches)
Hope this helps.
Well I don't know anything about Openshift but...
It's probably a maintenance or something (google gave me this https://openshift.redhat.com/community/forums/openshift/planned-outages, it's at the bottom).
EDIT: Example,
Your card list was originally
Card 1 Card 2 Card 3
Card 4 Card 5 Card 6
Card 7 Card 8 Card 9 ...
And the sleeve order is
524
413 <- the 2 was missing
135
What is the card in the bold space now?
BTW, does anyone have any information on pack removals? I still don't understand 100%.